18x^2-6x-89=0

Solution for 18x^2-6x-89=0 equation:

18x^2-6x-89=0

a = 18; b = -6; c = -89;
Δ = b2-4ac
Δ = -62-4·18·(-89)
Δ = 6444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6444}=\sqrt{36*179}=\sqrt{36}*\sqrt{179}=6\sqrt{179}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{179}}{2*18}=\frac{6-6\sqrt{179}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{179}}{2*18}=\frac{6+6\sqrt{179}}{36}
$